Question

How are we supposed to solve this question!?​

Answer 1

Concept: In fig we are given with the measurement of the base side and the hypotenuse side of a right-angled triangle but, we are not given with the measurement of the perpendicular of the same triangle. We are asked to find the same. We can find the value of the perpendicular by a simple concept named as Pythagoras theorem. This property is only applicable for any right-angled triangles. This property is used to find the value of any side of a right-angled triangle, in which we should be given with two sides.

Solution:

Base² + Perpendicular² = Hypotenuse ²

Write the names of the sides given in triangle.

→ BC² + AB² = AC²

Substitute the values of the sides.

→ 8² + X² = 10²

Find the square numbers of both numbers given.

→ 64 + X² = 100

Shift the number 64 from LHS to RHS, changing it's sign.

→ X² = 100 - 64

Subtract the values on RHS.

→ X² = 36

Remove square on LHS and insert square root on RHS

→ X = √36

Find the square root of 36 to get the answer.

→ X = 6cm.

Answer: So, the perpendicular measures is 6cm.

Answer 2

Answer:

use pythagorean's theorem; x=6

Step-by-step explanation:

a^2 + b^2 = c^2

a=length; b(x)=height; c= hypotenuse (longest side)

8^2 + b^2 = 10^2

64 + b^2 = 100 (subtract 64 from each side)

b^2= 36

6 x 6 = 36 so b=6

x=6