Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms
I hope this helps you
2a.2a+1.2a-3.2a-3.1
4a^2+2a-6a-3
4a^2-4a-3
Answer:1) commutative property of addition
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
PERT estimate is a measuring strategy that is based on a weighted average. It is used in measuring the uncertainty and risk via three estimates to determine an estimated likelihood for a project's cost or period of completion.
The formula is (O + 4M + P) ÷ 6
Where P is the most pessimistic = 29
M is the most likely = 12
O is the most optimistic = 10
Hence we have (10 + [4*12]+ 29) ÷ 6
= (10 + 48 + 29) ÷ 6
= 87÷6 = 14.5 ≈ 15
Rounded figure is equal to 15.
Hence the final answer to the question is 15
x ≤ 2.6 would look like this on the number line, the 2.6 part would be shaded in as well and not left open since x is less than OR EQUAL to 2.6