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3 years ago

An 8-ounce bag of candy is on sale for $1.12. What is the cost of 1 ounce of this candy?

Mathematics

2 answers:

Darya [45]3 years ago

8 0

Answer:

0.14

Step-by-step explanation:

boyakko [2]3 years ago

8 0

Answer: $0.14 or 14 cents

Step-by-step explanation:

If 8 ounce bag of candy cost $1.12 then to find out how much 1 ounce will cost will have to divide the money by 8.

1.12 / 8 = 0.14

So 1 ounce will 14 cents

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Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand

SOVA2 [1]

Answer:

Question 1:

(a) P(x<60) = 0.9236

(b) P(x>16) = 0.9564

(c) P(16<x<60) = 0.88

(d) P (x>60) = 0.0764

Question 2:

(a) P(x<3) = 0.0668

(b) P(x>7) = 0.0062

(c) P(3<x<7) = 0.927

Step-by-step explanation:

Question 1:

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

= P(z < 20/14)

= P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

= P(z>-1.71)

= 1 - P(z<-1.71)

= 1 - 0.0436

P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

= P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

P(16<x<60) = 0.9236 - 0.0436

P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

we have calculated P(x<60) in part (a) so,

P(x>60) = 1 - 0.9236

P (x>60) = 0.0764

Question 2:

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

= P(z<-1.5)

P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

= 1 - P(z<(7-4.5)/1)

= 1 - P(z<2.5)

= 1 - 0.9938

P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

we have computed both of these probabilities in parts (a) and (b) so,

P(3<x<7) = 0.9938 - 0.0668

P(3<x<7) = 0.927

6 0

3 years ago

Find an expression for the nth term ( tn ) in each of the following sequences:

Alexandra [31]

Answer:

The expression for the nth term is Tn = 8n -7

Step-by-step explanation:

Here, we are to find an expression for the nth term of the sequence.

Mathematically, the nth term of an arithmetic sequence can be expressed as;

Tn = a + (n-1)d

for T2, the equation is

a + d = 9

for T4, the equation is

a + 3d = 25

we can substitute the equation of T2 into T4 but we first need to rewrite T4

a + d + 2d = 25

9 + 2d = 25

2d = 25 -9

2d = 16

d = 16/2

d = 8

now since a + d = 9

a = 9-d

a = 9-8

a = 1

So the expression for the nth term would be;

1 + (n-1)8

1 + 8n - 8

= 8n -8+1

= 8n -7

6 0

3 years ago

How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.

Vaselesa [24]

Answer:

see below

Step-by-step explanation:

$-2(4 - \frac{x}{2} )^{5} + C$

Think of the above as:

$-\frac{2}{1}$ * $(\frac{8}{2} - \frac{x}{2} )^{5} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{2^{5}} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{32} + C$

= $-\frac{1}{1}$ * $\frac{(8 - x)^{5}}{16} + C$

= $\frac{-1(8 - x)^{5}}{16} + C$

= $\frac{(-8 + x)^{5}}{16} + C$

Can flip it around to be...

$\frac{(x - 8)^{5}}{16} + C$

4 0

3 years ago

What is an easy way to factor and equation like 2x^2-5x+3, without using the British method?

gladu [14]

Answer:

Step-by-step explanation:

I learned this easy way to complete the sqare in the fastest way possible

First you want to get it to x^2. So the first thing you would do is divide the entire equation by 2 to get 2(x^2 -5/2x +3/2). then you do one half of b or in this case -5/2. That would make -5/4. you would put this into the factor.

2( x -5/4 + ) ( x -5/4 - )

Then you square that number (-5/4)

That makes 25/16. you take that number and subtract the last number or the constant, c to make 1/16. now to finish it up you square root that number. the squre root of 1/16 is 1/4. then you put that into the last part of the factor.

2( x -5/4 + 1/4) ( x -5/4 - 1/4)

Then you simplify

(x-1) 2(x-3/2)

(x-1) (2x-3)

now to make sure I am correct, I will re-multiply it out

2x^2 -5x + 3

3 0

3 years ago

Which is the graph of the function f(x) = x³ + x² + x + 1?

lisabon 2012 [21]

Theres no graphs but this is how the function looks like

8 0

2 years ago