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Solnce55 [7]
3 years ago
9

(05.01)

Mathematics
1 answer:
Schach [20]3 years ago
8 0

Answer:

i think it's -1/2

Step-by-step explanation:

count the rise/run

up 2, to the left 1

-1-2

hope this helps!

You might be interested in
.
I am Lyosha [343]
Central angle  = 360 / 24  = 15 degrees

ARc length =  r * theta,    where theta is the angle in radians  and r = radius
                  = 15 * 15 * pi/180  
                  =  3.93 feet to nearest hundredth.

Area of sector =  area of circle / 24  = pi*15^2 / 24 =  29.45 ft^2 
6 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
4 years ago
What is the surface area of a cube whose edges are 11 inches long?
Pepsi [2]
11 * 11 * 6 = 726 square inches
7 0
3 years ago
Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward
Andru [333]
Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k

-24=3a
divide both sides by 3
-8=a

-2=a+k
-2=-8+k
add 8 to both sides
6=k

the equation is
y=-8(x-4)^2+6
3 0
3 years ago
Can someone help! I know the answer I just need step by step!
baherus [9]

Answer:

4 \sqrt{2}

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

\implies \sqrt{32}=\sqrt{16 \cdot 2

Apply exponent rule \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}

Rewrite 16 as 4²:

\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}

Apply exponent rule \sqrt{a^2}=a

\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}

6 0
3 years ago
Read 2 more answers
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