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3 years ago

Which circle has a central angle that measures 40°?

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Answer:

Option B.

Step-by-step explanation:

We need to find the circle that has a central angle that measures 40°.

In all options, the center of circle is U. It means central angle must be on center, i.e., U.

In option A,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.

In option B,the angle VUZ is at point U which is the center. So, angle VUZ is a central angle with measure 40°.

In option C,the angle XZV is at point Z which is not the center. So, angle XZV is not a central angle.

In option D,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.

Therefore, the correct option is B.

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Read 2 more answers

Amy purchased a brand-new mountain bike, which she's riding through

Neko [114]

Answer:

The Acceleration of bike after 3 minutes of ride is 14 meter² per minutes

Step-by-step explanation:

Given as :

The displacement of bike is the function of time

i.e s(t) = t³ - 2 t² + 3 meters

The Time of bike acceleration = t = 3 minutes

Let The Acceleration of bike = a meter² per minutes

Now, According to question

∵ <u>Acceleration is define as the rate of change of velocity</u>

i.e acceleration = $\dfrac{\textrm velocity}{\textrm time}$

or, a = $\dfrac{\textrm v}{\textrm t}$

And

<u>Velocity is define as rate of change of displacement</u>

i.e velocity = $\dfrac{\textrm displacement}{\textrm time}$

Or, v = $\dfrac{\textrm s}{\textrm t}$

Since here displacement is function of time

So , v = $\frac{\partial s(t)}{\partial t}$

Or, v = $\frac{\partial (t³ - 2 t² + 3)}{\partial t}$

Or, v = 3 t² - 4 t + 3

So, velocity is the function of time = v = 3 t² - 4 t + 3 meter per minutes

Now, Again

Acceleration = a = $\frac{\partial v}{\partial t}$

Or, a = $\frac{\partial (3 t² - 4 t + 3)}{\partial t}$

Or, a = 6 t - 4

∴ Acceleration is the function of time = a = 6 t - 4

Now, Acceleration of bike after 3 minutes

So, at t = 3 min

i.e a = 6 t - 4

Or, a = 6 × 3 - 4

Or, a = 18 - 4

∴ a = 14 meter² per minutes

Hence, The Acceleration of bike after 3 minutes of ride is 14 meter² per minutes . Answer

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