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vladimir1956 [14]
2 years ago
10

I’m not really sure how to work this out can someone plssss help me

Mathematics
1 answer:
Blizzard [7]2 years ago
6 0

Answer:

Perimeter of the rectangle=Perimeter of the trapezium

2{(3x+4)+(4x)}=2(5x)+(x-3)+(7x-3)

→2(7x+4)=10x+x-3+7x-3

→14x+8=18x-6

→4x=14

→x=7/2

<u>→</u><u>x=3.5</u>

The value of x is <u>3.5 cm</u>

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The graph of a line passes through the points (0, 5) and (-10, 0). What is the equation of the line?
natta225 [31]
First find the slope:
y-y/x-x
5-0/0-(-10
5/+10
slope: 1/2
then use:
y-5. 1
--- = ---
x-0. 2
cross multiply.
2 (y-5)=1 (x-0)
2y-10=x
move the ten to the other side, switch the sign
2y=x+10
divide by 2
y=1/2x+5
final answer is
y=1/2x+5
5 0
3 years ago
Read 2 more answers
What is the equation of the line that is perpendicular to the line y=3/5xplus 10 and passes through the point (15,-5)?
Allisa [31]

Step-by-step explanation:

a general line equation is

y = ax + b

the original line is

y = 3/5 x + 10

the factor of x is always the slope (inclination of the line).

it is "y change/x change".

the slope of a perpendicular line (angle of 90°) is turning the slope of the original line upside-down and flips the sign.

so, it is -5/3.

we use the point information to get the right "b" for our new line :

-5 = -5/3 × 15 + b

-5 = -5×5 + b

-5 = -25 + b

b = 20

so, the perpendicular line equation going through (15, -5) is

y = -5/3 x + 20

7 0
2 years ago
What is the common ratio for geometric sequence: 5,15,45,135 ?​
serg [7]

Answer:

the common ratio is 3

Step-by-step explanation:

to solve for the common ratio, I like to take the second term and divide it by the first term

15/5 = 3

then I will check the rest of the terms

15*3 = 45

45*3 = 135

It looks like the common ratio is correct!

5 0
2 years ago
Jordan saved 4/5 of the amount he needs to buy a $90 video game. If he earns $7.75 per hour by working at a pizza shop, how many
Slav-nsk [51]

Jordan has to work 2.3 hours to have enough money for the video game.

6 0
2 years ago
A steep mountain is inclined 74 degree to the horizontal and rises to a height of 3400 ft above the surrounding plain. A cable c
8_murik_8 [283]

Answer:

3854ft

Step-by-step explanation:

By assuming that the cable is not doubled.

in order to find the length of the base of the mountain

tan74°=3400/x

x= 3400/tan74°

x≈ 975ft

Therefore, the length of the cable equals to

            =\sqrt{3400^2+(975 + 840)^2}

length≈ 3854ft

Thus, the shortest length of cable needed is 3854ft

3 0
3 years ago
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