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3 years ago

10

3-6(1 +n) I don’t need the variable solve

1 answer:

Olegator [25]3 years ago

5 0

Answer:

-6n -3

Step-by-step explanation:

I'm assuming that if you don't need the variable solved, then you need it converted? here's another form.

You might be interested in

Factor out the coefficient of the variable 5/6s+2/3

DochEvi [55]

Okay. so I'm gonna assume you know what factor out means--were gonna take out 5/6. what we need to know is, how does that affect our ending number 2/3? well, we're gonna have 5/6 times some stuff first off, right?

5/6 ( )

so what's in the parenthesis? well, if we distribute in our mind, S would just have to be by itself for it to work out. so we have

5/6 ( s )

but what about 2/3? well, if we're multiplying everything on the inside by 5/6, how can be get it to cancel and leave 2/3 alone? we could divide 2/3 by 5/6, right?

5/6 ( s + (2/3) / (5/6) )

now, when we distribute our 5/6, we'll have just 2/3 at the end. now let's simplify that end term so it looks a little better. if we divide by a fracion, that's the same as multiplying by the flipped version, so let's do that.

2/3 / 5/6 = 2/3 × 6/5 = 2 (6) / 5 (3) = 12/15

we can reduce 12/15 by dividing the top and bottom by three.

= 4/5

so our final answer would be:

5/6 [S + 4/5] you can redistribute to make sure it matches. Anyway, hope that helps!

6 0

3 years ago

Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present ag

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

$M = 6S$

$S + 5 = \frac{1}{3}M$

where $S$ is the current age of Shobos and $M$ is the current age of his mother.

Substituting the first equation into the second will allow us to solve for $S$ :

$S + 5 = \frac{1}{3}M$

$S + 5 = \frac{1}{3}(6S)$

$S + 5 = 2S$

$S = 5$

Substituting this value into the first equation gives us the age of the mother:

$M = 6S$

$M = 6(5)$

$M = 30$

5 0

3 years ago

Read 2 more answers

Someone please help me with this lol… have no idea what I’m doing

Sholpan [36]

Given:

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

To find:

The quadrant of the terminal side of $\theta$ and find the value of $\sin\theta$ .

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

Here cos is positive and sine is negative. So, $\theta$ must be lies in Quadrant IV.

We know that,

$\sin^2\theta +\cos^2\theta =1$

$\sin^2\theta=1-\cos^2\theta$

$\sin \theta=\pm \sqrt{1-\cos^2\theta}$

It is only negative because $\theta$ lies in Quadrant IV. So,

$\sin \theta=-\sqrt{1-\cos^2\theta}$

After substituting $\cos \theta =\dfrac{3}{5}$ , we get

$\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}$

$\sin \theta=-\sqrt{1-\dfrac{9}{25}}$

$\sin \theta=-\sqrt{\dfrac{25-9}{25}}$

$\sin \theta=-\sqrt{\dfrac{16}{25}}$

$\sin \theta=-\dfrac{4}{5}$

Therefore, the correct option is B.

6 0

3 years ago

tina has 50 coins, all dimes and quarters. the value of the coins is $7.10. write a system of equations to determine how many di

Sliva [168]

Answer:

A) D + Q = 50

B) .10D + .25Q = 7.10

We multiply A) by -.10

A) -.10D - .10Q = -5 then adding this to B)

B) .10D + .25Q = 7.10

.15Q = 2.10

Quarters = 14 = 3.50

Dimes = 36 = 3.60

Step-by-step explanation:

7 0

3 years ago

I need help on B!!!! i need explanation +math

jekas [21]

It shows that six years pasted between 2007 and 2013 and it increased by 20,000 so add that to the population at the time the answer is 158000

5 0

3 years ago