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Travka [436]
3 years ago
7

For the data set: {1.5, 2.3, 1.7, 3.6, 2.9, 4.2}, identify the percentile for the value 2.9.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

58.33%.

Step-by-step explanation:

We have been given a data set {1.5, 2.3, 1.7, 3.6, 2.9, 4.2} and we are asked to find the percentile for value 2.9.

First of all let us arrange our data points from smallest to largest as: {1.5, 1.7, 2.3, 2.9, 3.6, 4.2}.    

We can see that our data set has 6 data points and 2.9 is 4th data point.  

We will use percentile rank formula to solve our problem.  

P=\frac{(100*(i-0.5))}{n}, where,

P= Percentile rank,

i= Rank of the data point,

n = Total number of data points.

Upon substituting our given values we will get,

P=\frac{(100*(4-0.5))}{6}

P=\frac{(100*3.5)}{6}

P=\frac{350}{6}

P=\frac{350}{6}

P=58.333  

Therefore, percentile rank for the value 2.9 is 58.33%.

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5 0
3 years ago
17x-3y=4 2x-4y=1 the solution to the system of equations is
Burka [1]

ANSWER

x=\frac{13}{62}

and


y= \frac{-9}{62}e have



EXPLANATION




17x-3y=4---(1)


2x-4y=1



Let us make y the subject and call it equation (2)


2x=1+4y


x=\frac{1}{2}+2y--(2)



We put equation (2) in to equation (1)




17(\frac{1}{2}+2y)-3y=4


\frac{17}{2}+34y-3y=4



34y-3y=4- \frac{17}{2}


Simplify to get,



31y= \frac{8-17}{2}



31y= \frac{-9}{2}


Divide both sides by 31,



y= \frac{-9}{2} \div 31



y= \frac{-9}{2} \times \frac{1}{31}




y= \frac{-9}{62}


We put this value in to equation (2) to get,



x=\frac{1}{2}+2\times -\frac{9}{62}




x=\frac{1}{2} -\frac{18}{62}


We collect LCM to obtain,



x=\frac{31-18}{62}



x=\frac{13}{62}








7 0
3 years ago
Please help please cfgyy
Alenkinab [10]
3x- 11 +59 = 90
3x + 48 = 90
3x +48-48 =90-48
3x = 42
3x/3 = 42/3
x= 14

<MNQ = 3x -11
<MNQ = 3(14)-11
<MNQ = 42-11
<MNQ = 31
7 0
3 years ago
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