Question

As a plane takes off it ascends at a 20 degree angle of elevation. If the plane has been traveling at an average rate of 290 ft/s and continues to ascend at the same angle, then how high is the plane after 10 seconds (the plane has traveled 2900ft).

Answer 1

Given :

As a plane takes off it ascends at a 20 degree angle of elevation.

If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.

To Find :

How high is the plane after 10 seconds.

Solution :

Distance travelled by plane, D = 2900 ft.

Angle of elevation, Ф = 20°.

Height gained is given by :

$H = Dsin\ \phi$

H = 2900 × sin 20°

H = 991.86 ft.

Therefore, height of plane after 10 seconds is 991.86 ft.

Hence, this is the required solution.