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3 years ago

Which line in the graph has the equation y= 1/2x + 2

Mathematics

1 answer:

Alexxx [7]3 years ago

4 0

Answer:

Step-by-step explanation:

y= mx +b

b the y-intercept and is 2 so is red or purple line

m is the slope = 1/2 so rise 1 and run 2 is the purple line

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Sketch a graph of −3x+y=2

DIA [1.3K]

You can do this by first finding the y intercept which is the point where x = 0

-3(0) + y = 2
so y intercept is the point (0,2)

Now find the x intercept by putting y = 0

-3x = 2

x = -2/3

So we have 2 points (-2/3, 0) and (0,2) Draw a line through these 2 points and you have the required graph.

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3 years ago

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Simplify the square root of -18

Levart [38]

The square root of -18 is 3i√ 2

Hope this helps

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3 years ago

|r|=-2 solve the equation and graph the solution if possible

S_A_V [24]

That bracket symbol, with an r in it, means "the absolute value of r".
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3 years ago

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mr Goodwill [35]

Answer:

It would be 6.8

8 0

3 years ago

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Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third

Andrei [34K]

<h3>The equivalent expression is:</h3>

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Solution:

Given expression is:

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}$

We have to find the equivalent expression

We can simplify the above expression using law of exponents

Use the following law of exponents:

$a^m \times a^n = a^{m+n}$

Therefore,

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}$

Use another law of exponent

$(a^m)^n = a^{mn}$

Therefore,

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Thus the equivalent expression is found

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3 years ago

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