The first step is to multiply the fraction by (3 +3i) / (3 +3i) to delete the i terms from the denominator:

I will be using the language C++. Given the problem specification, there are an large variety of solving the problem, ranging from simple addition, to more complicated bit testing and selection. But since the problem isn't exactly high performance or practical, I'll use simple addition. For a recursive function, you need to create a condition that will prevent further recursion, I'll use the condition of multiplying by 0. Also, you need to define what your recursion is.
To wit, consider the following math expression
f(m,k) = 0 if m = 0, otherwise f(m-1,k) + k
If you calculate f(0,k), you'll get 0 which is exactly what 0 * k is.
If you calculate f(1,k), you'll get 0 + k, which is exactly what 1 * k is.
So here's the function
int product(int m, int k)
{
if (m == 0) return 0;
return product(m-1,k) + k;
}
Answer:
39/50 and 0.78
Step-by-step explanation:
78% = 78/100 (or 78 hundredths) = 0.78
39 ÷ 50 = 0.78
Notice the picture,
recall your SOH, CAH, TOA

you have,
opposite side, 165
adjacent side, 50
and the angle
that means, we'll need Mrs. tangent
thus