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kodGreya [7K]
3 years ago
12

Simplify the square root of -18

Mathematics
1 answer:
Levart [38]3 years ago
4 0

The square root of -18 is 3i√ 2

Hope this helps


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Please help me solve this problem
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3

Step-by-step explanation:

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Maria used one bag of flour. She baked
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48 pounds

Step-by-step explanation:

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Julianne earned $296 working at a grocery store last week. She earned $8 per hour. How many hours did Julianne work?
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What value of x is in the solution set of –2(3x + 2) &gt; –8x + 6?<br><br> –6<br> –5<br> 5<br> 6
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Step-by-step explanation:

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3 years ago
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The height h(n) of a bouncing ball is an exponential function of the number n of bounces.
Digiron [165]

Answer:

The height of a bouncing ball is defined by h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}.

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

h = h_{o}\cdot r^{n-1}, n \in \mathbb{N}, 0 < r < 1 (1)

Where:

h_{o} - Height reached by the ball on the first bounce, measured in feet.

r - Decrease rate, no unit.

n - Number of bounces, no unit.

h - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

r = \frac{h_{1}}{h_{o}} (2)

Where h_{1} is the height reached by the ball on the second bounce, measured in feet.

If we know that h_{o} = 6\,ft and h_{1} = 4\,ft, then the expression for the height of the bouncing ball is:

h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}

The height of a bouncing ball is defined by h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}.

5 0
3 years ago
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