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kati45 [8]
2 years ago
6

Identify the true statements if ∆XWT - ∆YAQ.

Mathematics
1 answer:
Natali [406]2 years ago
5 0

Answer:

Step-by-step explanation:

Its A and c

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Joe read 140 pages of his 300 page book what percent of his book has he read
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Answer:

47

Step-by-step explanation:


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3 years ago
Tamara needs $624 for her budget every week. She works 40 hours a week.
kirza4 [7]

Answer:

$15.6

Step-by-step explanation:

Based on the given information, it is $15.6. However, it never specified how many hours she works a day and how many days of the week she works, so we must assume it is just 624/40.

3 0
2 years ago
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Robert run the 100 meter dash in 13.5. later he run same distance in 10.3 seconds. how many seconds less did it take him to run
leonid [27]

Answer:

3.2seconds

Step-by-step explanation:

Step one:

Robert run the 100 meter dash in 13.5 seconds

We are told that he later  run same distance in 10.3 seconds

Required.

The time difference in the first dash and the second

Step two:

The first dash took 13.5 seconds

the second took 10.3 seconds

the difference = 13.5-10.3= 3.2seconds

3 0
2 years ago
Ms.Lopez has 4 liters of chemicals that she is going to pour into beakers. Each beaker will have 1/4 of a liter of chemicals, ho
Yakvenalex [24]
It would be 256 because you would do 4 to the power of 4
6 0
3 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
5 0
2 years ago
Read 2 more answers
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