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ycow [4]
3 years ago
15

What is the zero of the function below? f(x)=3 square root x+3 -6x=1x=-1x=9x=-3

Mathematics
2 answers:
loris [4]3 years ago
7 0

Answer:

x=1

Step-by-step explanation:

Given function,

f(x)=3\sqrt{x+3}-6

Since, the zeroes of a function are those input values for which the function gives the output zero,

So, for the zeroes of f(x),

f(x) = 0

\implies 3\sqrt{x+3}-6=0

3\sqrt{x+3}=6      ( Adding 6 on both sides )

\sqrt{x+3}=2        ( Dividing both sides by 3 )

x+3=4                ( Taking square of both sides )

x = 1                   ( Subtracting 3 from both sides )

Hence, the zero of the given function is, x = 1.

First option is correct.

ddd [48]3 years ago
5 0

Answer:

<h2>x = 1</h2>

Step-by-step explanation:

f(x)=3\sqrt{x+3}-6\\\\\text{Domain:}\ x+3\geq0\to x\geq-3\\\\\text{The zero}\to f(x)=0\\\\3\sqrt{x+3}-6=0\qquad\text{add 6 to both sides}\\\\3\sqrt{x+3}=6\qquad\text{divide both sides by 3}\\\\\sqrt{x+3}=2\iff x+3=2^2\\\\x+3=4\qquad\text{subtract 3 from both sides}\\\\x=1

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