Answer:
25m
Step-by-step explanation:
Area = Side²
Side = √Area
= √625
= √25 x 25
= 25 m
Answer:
90
Step-by-step explanation:
First, we should find the area of the trapezoid, and then subtract the area of the removed triangle in order to find the shaded area.
Area of the trapezoid
1) Area of the rectangle in the middle.
Base Length: 10
Height Length: 10
Area: 10 x 10 = 100
2. Area of the triangles on the side
Base Length: (14 - 10)/2 = 2
Height Length: 10
Area: 2 x 10 x 1/2 = 10
There are two triangles: 10 x 2 = 20
Area of the trapazoid: 100 + 20 = 120
Area of the triangle that's been removed
Base Length: 10
Height Length: 10 - 4 = 6
Area: 10 x 6 x 1/2 = 30
Shaded area
Area of the trapezoid - Area of the triangle
120 - 30 = 90
Area of the shaded region is 90.
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer: 5$ in all
Step-by-step explanation:
I added 3 + 2 dollars in all
Answer:
x = 14
Step-by-step explanation:
comp = add up to be 90
3x + 14 + 2x + 6 = 90
5x + 20 = 90
5x = 70
x = 14
