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2 years ago

Which equation is equivalent to log3(x+5)=2

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

6 0

Answer:

10^2=3(x+5)

Step-by-step explanation:

good luck!

Darina [25.2K]2 years ago

4 0

In exponential form: 10^2=3(x+5)
If we were to solve, x=85/3

You might be interested in

2 (-n -3) -7 (5 + 2n)

leonid [27]

Answer: -16n-41

Step-by-step explanation:

first, distribute 2 through the parentheses:

2(-n-3)-7(5+2n) = -2n-6-7(5+2n)

second, distribute 7 through the parenthesis:

-2n-6-7(5+2n) = -2n-6-35-14n

Collect like terms:

-2n-6-35 and -16n-6-35

Calculate the difference:

-2n-6-35-14n = -16n-41

SOLUTION:

-16n-41

7 0

2 years ago

Hii can someone explain to me how to do this? tyvm

Snezhnost [94]

Step-by-step explanation:

it's late but I hope it helps :)

imagine that the > symbol is just an equal sign

so for example

x+2>4

will look like

x+2=4

and you solve normally

×=2

now we bring the symbol back

x>2

but if you multiple or divide by a negative the sign flips

so say you have

-2x>4

make it into

-2x=4

solve

x=-2

but instead of >

you put

x < -2

5 0

2 years ago

The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in sl

DerKrebs [107]

<h3>Answer:</h3>

y=-5x-2

<h3>Solution:</h3>

We are given the line's slope and a point that it passes through.
Using the given information, we can write the equation of the line in Point-Slope Form:
$y-y_1=m(x-x_1)$
In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
Plug in the values:
y-(-12)=-5(x-2)
y+12=-5(x-2)
Now, convert into Slope-Intercept Form, y=mx+b:
y+12=-5x+10
y=-5x+10-12
y=-5x-2

Hope it helps.

Do comment if you have any query.

5 0

2 years ago

∫∫(x+y)dxdy ,d là miền giới hạn bởi x²+y²=1

igor_vitrenko [27]

It looks like you want to compute the double integral

$\displaystyle \iint_D (x+y) \,\mathrm dx\,\mathrm dy$

over the region D with the unit circle x ² + y ² = 1 as its boundary.

Convert to polar coordinates, in which D is given by the set

D = {(r, θ) : 0 ≤ r ≤ 1 and 0 ≤ θ ≤ 2π}

and

x = r cos(θ)

y = r sin(θ)

dx dy = r dr dθ

Then the integral is

$\displaystyle \iint_D (x+y)\,\mathrm dx\,\mathrm dy = \iint_D r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \int_0^{2\pi} \int_0^1 r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \underbrace{\left( \int_0^{2\pi}(\cos(\theta)+\sin(\theta))\,\mathrm d\theta \right)}_{\int = 0} \left( \int_0^1 r^2\,\mathrm dr \right) = \boxed{0}$

3 0

2 years ago

Select all of the factors of x3 + 5x2 + 2x – 8.

gladu [14]

The factors of this polynomial would be (x + 4)(x + 2)(x - 1).

To find these, you first have to start with long division to find the first factor. If you use x + 4 it would look like this.

$\frac{x^{3} + 5x^{2} + 2x - 8}{x + 4}$ = $x^{2} + x - 2$

Now we are left with only $x^{2} + x - 2$ . We can factor this by looking for numbers that multiply to the last number and add to the middle number. 2 and -2 multiply to -2 and add to 1. Therefore, we'll use those in parenthesis in their place.

(x + 4)(x + 2)(x - 1)

5 0

2 years ago

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