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Marina86 [1]
3 years ago
5

Describe a situation that could be represented by -8

Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0
Hmm.. Maybe a situation such as: A sports team lost eight points during their game. How is this presented as an integer?
Alexandra [31]3 years ago
4 0

Answer:

Maybe something like this -

A dance team lost 8 points last performance they performed.

Sorry if it isn't good! ^-^

Step-by-step explanation:

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What is the solution to this equation?<br> x-8=15<br><br> A)x=13<br> B)x=17<br> C)x=7<br> D) x=23
Blababa [14]

Hi there! :)

<u><em>Answer:</em></u>

<u><em>x=23</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

Step-by-step explanation:

This lesson it's about addition property of equality.

First, you add by 8 from both sides of an equation.

x-8+8=15+8

And then, you add by the numbers. Simplify and solve.

15+8=23

Final answer: → x=23

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

3 0
3 years ago
What is the cube root of 2197
kifflom [539]
13. I hope this helped. :) Brainliest answer please. :)
3 0
3 years ago
Read 2 more answers
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
The measure of ∠FHJ is 60°. The measure of ∠FGH is 28°.<br><br><br><br> What is the measure of ∠HFG?
Hatshy [7]
<span>Given
∠FHJ = 60°
</span><span>∠FGH =  28°

</span>∠FHG = 180 - ∠FHJ
∠FHG = 180 - 60
∠FHG = 120


∠HFG = 180 - (28 + 120)
∠HFG = 180 - 148
∠HFG = 32

6 0
3 years ago
Can someone help with this question
KatRina [158]
I think it’s 7 Becuase the Ae and DE are congruent
4 0
2 years ago
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