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3 years ago

Describe a situation that could be represented by -8

2 answers:

6 0

Hmm.. Maybe a situation such as: A sports team lost eight points during their game. How is this presented as an integer?

Alexandra [31]3 years ago

4 0

Answer:

Maybe something like this -

A dance team lost 8 points last performance they performed.

Sorry if it isn't good! ^-^

Step-by-step explanation:

You might be interested in

What is the solution to this equation? x-8=15 A)x=13 B)x=17 C)x=7 D) x=23

Blababa [14]

Hi there! :)

Answer:

x=23

*The answer must have a positive sign.*

Step-by-step explanation:

This lesson it's about addition property of equality.

First, you add by 8 from both sides of an equation.

$x-8+8=15+8$

And then, you add by the numbers. Simplify and solve.

$15+8=23$

Final answer: → $x=23$

Hope this helps!

Thanks!

-Charlie

Have a great day!

3 0

3 years ago

What is the cube root of 2197

kifflom [539]

13. I hope this helped. :) Brainliest answer please. :)

3 0

3 years ago

Read 2 more answers

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$