26s? + 33 Submit Hzhjskapskdjsjababah

liq [111]

Divide both sides by 5

e^x=3.152 take the natural log of both sides...

x=ln(3.152)

x≈1.148

3 0

3 years ago

A rock is dropped off a 500-foot cliff. After 1 second the rock is traveling 32 feet per second then after 4 seconds the rock st

kozerog [31]

Answer:

A. The equation describing the relationship between speed and time is:

s = 32t

Ordered pairs of the form (speed, time) are:

(32, 1)

(64, 2)

(96, 3)

(128, 4)

B.

Using s = 32t, we have:

s = 32 * 5 = 160 feet per second

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Height of the cliff = 500 feet

Speed after one second = 32 feet per second

Speed after four seconds = 128 feet per second

2. Assume the relationship between time, t, and speed, s, is linear and write an equation describing the relationship. Use ordered pairs of the form (speed, time)

The equation describing the relationship between speed and time is:

s = 32t

Ordered pairs of the form (speed, time) are:

(32, 1)

(64, 2)

(96, 3)

(128, 4)

3. Use the equation to determine the speed of the rock 5 seconds after is dropped.

s = 32t

s = 32 * 5 = 160 feet per second

Note: Same answer to question 14436233, answered by me today.

4 0

3 years ago

Alybia was making 115 cookies for a Valentine’s Day party. They were each either red or purple. Forty percent of the cookies wer

NeTakaya

Answer:

69 purple cookies!

Step-by-step explanation:

7 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

What is 11918 as a mixed number in simplest form? Enter your answer in the box.

sveta [45]

Answer:

the answer is 11 1/2.

Step-by-step explanation:

I used a calculator

8 0

3 years ago

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