If a number is a multipule of 6 then it is a multiplule of 2 AND 3
if a number is a multiplule of 2 then the last digit should be divisible by 2 (ie, 0,2,4,6,8)
if a number is divisible by 3, then the sum of its digits is divisble by 3
try each
A. 333
last number is not divisible by 2 so not divisible by 6
B. 882
2 is divisible by 2
8+8+2=18
18/3=6
divisible by 6 yes
C. 424
4 is disibielbe by 2
4+2+4=10
10/3=not a whole number so not divisible by 6
D. 106
6 is divisible by 2
1+0+6=7
7/3= not a whole number so not divibislb eby 6
answer is B
29) Turns is the ratio of annual amount to average amount.
Cost turns = 57,982.85/15,545 ≈ 3.73
Sales turns = 130,935.60/35,388 ≈ 3.70
30) Consider January of the following year to be month 13.
7/16 to 13/14 is 6 months less 2 days. There are 31 days in July, August, October, and December, so 4 more days than 30 days per month. The total number of days is 6*30 -2 +4 = 182
31) I = Prt = $5380×0.118333×90/360 = $159.16
Answer:
(p + q)² - ∛(h·3k) or (p + q)² - ∛(h·3k)
Step-by-step explanation:
Cube root of x: ∛x
Product of h and 3k: h·3k
Sum of p and q: p + q
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From (p + q)² subtract ∛(h·3k) This becomes, symbolically:
=> (p + q)² - ∛(h·3k)
I believe that it's A neither, because I don't think that it could be displayed on a coordinate graph when it has an exponent in it. So I think it's A. Let me know if I'm correct. ;-)
8 = 4w/3 Original Problem.
4w/3 = 8 Flip Flopped the problem around.
4w = 24 Multiplied each side by 3.
w = 6 Divided each side by 4.
Answer: w = 6
