I’ve answered this question before, so please see the
attached image.
The solution would be like this for this specific problem:
1, 4, 5, 8 = 55<span>
2, 3 , 6, 7 = 125
9, 12, 13, 16 = 80
10, 11, 14 ,15 = 100</span>
<span>So, the angle measures that are correct are:
</span>
m12 = 100
m8 = 55
m14 = 100
<span>m16 = 80</span>
The total number of tries = 10
The tries are { <span>110 111 100 000 101 111 100 000 011 010 }
</span><span />
Where: 0 representing heads and 1 representing tails
The tries which are heads came up more than once in 3 coin flips { 100 000 100 000 010 }
The number of the tries which are heads came up more than once in 3 coin flips = 5
∴ The probability of heads coming up more than once in 3 coin flips = 5/10 = 1/2
Answer: 1/4
Step-by-step explanation:
Answer:
Step-by-step explanation:
