2x^2+2x-40=0
2x^2+10x-8x-40=0
2x(x+5)-8(x+5)=0
(2x-8)(x+5)=0
2(x-4)(x+5)=0
x=-5 and 4
If you graph it, the zeros are just the values of x when the curve meets the x axis...
Answer:
x=10
Step-by-step explanation:
I think..i tired
Divide both sides by 55.
{x}^{2}=-\frac{500}{5}x2=−5500
2
Simplify \frac{500}{5}5500 to 100100.
{x}^{2}=-100x2=−100
3
Take the square root of both sides.
x=\pm \sqrt{-100}x=±√−100
4
Simplify \sqrt{-100}√−100 to \sqrt{100}\imath√100ı.
x=\pm \sqrt{100}\imathx=±√100ı
5
Since 10\times 10=10010×10=100, the square root of 100100 is 1010.
