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Genrish500 [490]
3 years ago
14

What is the solution of each equation? Check your answer.

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

-6

Step-by-step explanation:

first you crossover negative 8 to make it positive then you add to -14

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Rom4ik [11]

y=x^2 + x - 2

x + y = 1

Replace y in the second equation:

x + x^2 + x -2 = 1

Simplify:

x^2 + 2x -2 = 1

Subtract 1 from both sides:

x^2 + 2x -3 = 0

Factor:

(x-1) (x+3) = 0

Solve for both x's:

x = 1 and x = -3

Now replace x in the second equation and solve for y using both x values:

1 + y = 1, y = 0

-3 + y = 1, y = 4

Now you have (1,0) and (-3,4) as solutions for (x,y)

XY = x times y:

1 x 0 = 0

-3 x 4 = -12

The answer would be -12

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