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2 years ago

Can someone help me find the diameter of the copper ball ty

Mathematics

1 answer:

Vladimir [108]2 years ago

5 0

Answer:

The answer is 346.185 if its diameter is 22.

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What is the sum of 1/4 1/8 and 3/8

antiseptic1488 [7]

1/4 + 1/8 + 3/8 = (2*1 +1 +3)/8 = (2+1+3)/8 = 6/8 = 3/4

hope helped

5 0

2 years ago

Read 2 more answers

Someone please help due tonight

Alika [10]

0=$5
1=$7
2=$9
3=$11
4=$13
5=$15
6=$17

4 0

2 years ago

The temperature in a city was recorded over a ten-hour period. The graph below shows the relationship between the temperature an

harkovskaia [24]

Answer:

Step-by-step explanation:

From the graph, we can see that the temperature increased initially, then started to decrease. All of these NOT in a constant rate, though.

Roughly, the temperature was increasing from start till around 5.5 hours. Then on the temperature decreased.

So we can eliminate B, C, and D. That leaves us with correct answer as A.

5 0

2 years ago

The area of a rectangle is 70 square inches.

german

The correct answer is A.

7 0

2 years ago

Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace

joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean $\mu$ and default $\sigma$ , then the mean take seriously given as the straight line with a z score given by the confidence interval

$\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\$

Using formula:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

$P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)$

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

$=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z$

the required probability: $P(z>0.8349)=1-P(z$

4 0

1 year ago