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atroni [7]
3 years ago
10

Solve the system of equations and choose the correct ordered pair.

Mathematics
2 answers:
evablogger [386]3 years ago
8 0
I hope this helps you

Ratling [72]3 years ago
6 0

Answer:

C.

Step-by-step explanation:

We are going to solve it with substitution, that is, we are going to clear one variable and then replace it in the other equation. Then,

3x + 2y = 12

3x = 12-2y

x = \frac{12-2y}{3}

x = \frac{12}{3}-\frac{2y}{3}

x = 4-\frac{2y}{3}.

Now, we replace that x value in the equation 6x + 3y = 21:

6(4-\frac{2y}{3}) + 3y = 21

24-\frac{12y}{3} + 3y = 21

24-4y + 3y = 21

24-y = 21

-y = 21-24

-y = -3

y = 3.

Finally, we replace the y value found to find x.

x = 4-\frac{2*3}{3}

x = 4-2

x = 2.

So, the solution is (x,y)=(2,3). Then, the answer is C.

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A rectangular prism has a volume of 600 cubic inches.
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Answer:

The length is 12 inches.

Step-by-step explanation:

The volume of a rectangular prism is given by:

V=LBH

It was given that; the rectangular prism has a volume of 600 cubic inches.

The height of the prism is 5 inches and the width is 10 inches.

We want to find the length of the rectangular prism.

We substitute V=600, H=5,and W=10 into the formula:

600=5×10×L

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5 0
3 years ago
What is the probability that a junior non-Nutrition major and then a sophomore Nutrition major are chosen at random? Express you
aleksandr82 [10.1K]

Answer:

0.0032

The complete question as seen in other website:

There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

Step-by-step explanation:

Total number of in a nutrition class = 111 students

To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.

Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)

Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)

There are 13 number of junior non-Nutrition major

Pr (j non-N) = 13/111

Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)

Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)

There are 3 number of sophomore Nutrition major

Pr (S N-major) = 3/111

The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111

= 39/12321

= 0.0032

7 0
3 years ago
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