I need help ASAP. Please answer this equation! Combine like terms.

For a certain population of men, 8 percent carry a certain genetic trait. For a certain population of women, 0.5 percent carry t

slavikrds [6]

Answer:

C) 150 men and 100 women

D) 200 men and 2000 women

E) 1000 men and 1000 women

Step-by-step explanation:

Hello!

To compare the proportion of people that carry certain genetic trait in men and woman from a certain population two variables of study where determined:

X₁: Number of men that carry the genetic trait.

X₁~Bi(n₁;p₁)

X₂: Number of women that carry the genetic trait.

X₂~Bi(n₂;p₂)

The parameter of interest is the difference between the population proportion of men that carry the genetic trait and the population proportion of women that carry the genetic trait, symbolically: p₁-p₂

To be able to study the difference between the population proportions you have to apply the Central Limit Theorem to approximate the distribution of both sample proportions to normal.

Reminder:

Be a variable with binomial distribution X~Bi(n;p), if a sample of size n is taken from the population in the study. Then the distribution of the sample proportion tends to the normal distribution with mean p and variance (pq)/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

So for both populations in the study, the sample sizes should be

n₁ ≥ 30

n₂ ≥ 30

Also:

Both samples should be independent and include at least 10 successes and 10 failures.

Both populations should be at least 20 times bigger than the samples. (This last condition is to be assumed because without prior information about the populations is impossible to verify)

If everything checks out then (p'₁-p'₂)≈N(p₁-p₂; p(1/n₁+1/n₂))

The options are:

A) 30 men and 30 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 30*0.08= 2.4

Failures: y₁= n₁*q₁= 30*0.92= 27.6

Population 2

Successes: x₂= n₂*p₂= 30*0.5= 15

Failures: y₂= n₂*q₂= 30*0.5= 15

The second condition is not met.

B) 125 men and 20 women

n₁ ≥ 30 but n₂ < 30

Both samples are independent but n₂ is not big enough for the approximation.

C) 150 men and 100 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 150*0.08= 12

Failures: y₁= n₁*q₁= 150*0.92= 138

Population 2

Successes: x₂= n₂*p₂= 100*0.5= 50

Failures: y₂= n₂*q₂= 100*0.5= 50

All conditions are met, an approximation to normal is valid.

D) 200 men and 2000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 200*0.08= 16

Failures: y₁= n₁*q₁= 200*0.92= 184

Population 2

Successes: x₂= n₂*p₂= 2000*0.5= 1000

Failures: y₂= n₂*q₂= 2000*0.5= 1000

All conditions are met, an approximation to normal is valid.

E) 1000 men and 1000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 1000*0.08= 80

Failures: y₁= n₁*q₁= 1000*0.92= 920

Population 2

Successes: x₂= n₂*p₂= 1000*0.5= 500

Failures: y₂= n₂*q₂= 1000*0.5= 500

All conditions are met, an approximation to normal is valid.

I hope this helps!

6 0

3 years ago

Fraction:

Zanzabum

Answer + step-by-step explanation:

7/10 as a decimal would be 0.7.

7/10 or 0.7 in a word form would be seven tenths.

Hope this helps, if my answer or explanation is wrong

feel free to message me in the comments :).

- genius423

6 0

3 years ago

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below

BARSIC [14]

Answer:

Due to the higher Z-score, Demetria should be offered the job.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Whichever applicant had grade with the highest z-score should be offered the job.

Demetria got a score of 85.1; this version has a mean of 61.1 and a standard deviation of 12.

For Demetria, we have $X = 85.1, \mu = 61.1, \sigma = 12$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{85.1 - 61.1}{12}$

$Z = 2$

Vincent got a score of 299.2; this version has a mean of 264 and a standard deviation of 22.

For Vincent, we have $X = 299.2, \mu = 264, \sigma = 22$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{299.2 - 264}{22}$

$Z = 1.6$

Tobias got a score of 7.26; this version has a mean of 7.1 and a standard deviation of 0.4.

For Tobias, we have $X = 7.26, \mu = 7.1, \sigma = 0.4$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{7.26 - 7.1}{0.4}$

$Z = 0.4$

Due to the higher Z-score, Demetria should be offered the job.

3 0

3 years ago

write an expression to describe a rule for the sequence. Then find the 100th term in the sequence 3, 10, 17, 24, 31, 38, ...

blagie [28]

As we can tell, the first number is 3, so we'll have a y-intercept in our equation and overall. Secondly, we can tell it's increasing by 7 each time, so we can tell that's the rate. But, it won't just be 3+7x, if we plug 1 in, it would be 10 and not 3. We need to put in the parenthesis 3+7(x-1). If we put one in, we would receive three. Let's make sure this works.
3+7(5-1)
3+7(4)
3+28
31
31 is the fifth terms.
So the expression would be 3+7(x-1).
Let's find the 100th term.
3+7(100-1)
3+7(99)
3+693
696
So the 100th term would be 696.

3 0

3 years ago

A farmer grows corn, tomatoes, and sunflowers on a 320-acre farm. This year, the farmer wants to plant twice as many acres of to

svet-max [94.6K]

Set it up with variables; tomatoes=t, sunflowers=s, corn=c

320=t+s+c

This year;
t=2s
c=t+40

so, replace 2s for t; c=2s+40

now we can put those factors in for 320=t+c+s

320= 2s+2s+40+s
(SIMPLIFY)---> 320=5s+40----> 5s+280----> s=56

now incorporate the s value into the other equations.

c=2s+40----> c=56(2)=40 ----> c=152
t=2s -----> t=2(56) ----> t=112

TOMATOES= 112 acres
CORN= 152 acres
SUNFLOWERS= 56 acres

To check your work: 320=t+s+c ----> 320=112+156+56

5 0

3 years ago

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