858 i believe...
546/7
78 x 4 (compound a)
312 + original compound b (546)
Hope I helped!
Giving me brainliest is much appreciated! =)
Hello! Your answer is B, 10 minutes.
Say the x = minutes taken to do the job. You can set up an equation like this to solve this.

This is representative of the situation. The fractions each represent <u>how much each person does in a minute</u>, and when they're multiplied by x, that's <u>how much of the project they get done</u> based off of the minutes they work together on the job. Add the two together, and you get <u>how much of the project is finished in x amount of time</u>. Set it equal to 1, as you are looking for 100% completion.
Once you have this equation, find a common denominator, add, and solve.





Therefore, it will take them 10 minutes to do the job together.
Hope this helps!
Formula for the perimeter of a quarter circle: C = ((pi x 2r) / 4) + 2r
C = ((3.14 x 18) / 4) + 18
C = (56.52 / 4) + 18
C = 14.13 + 18
C = 32.13 miles
Hope this helps! :)
The ordered pair is included in the solution set to the following system is (0,2)
<h3>Set of inequalities</h3>
Given the set of inequalities
y > x2 + 1
y < x2 – x + 1
Equate both expressions to have:
x^2 + 1 = x^2 - x +1
1 = -x + 1
x = 0
Substitute x = 0 into any of the function
y = x^2 + 1
y = 1
This shows that the ordered pair is included in the solution set to the following system is (0,2)
Learn more on inequality here: brainly.com/question/24372553
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Answer:
(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>
<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>
Step-by-step explanation:
Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>
x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>
<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:
→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>
Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>
<em>
</em>
<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

