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2 years ago

What is quartile 1 and 3

Mathematics

2 answers:

motikmotik2 years ago

4 0

Answer:

Q1 = 2

Q3 = 3

I think that's the answer

Hope this helps! (°◡°♡).:｡

Akimi4 [234]2 years ago

4 0

Answer:

Q1 is 2 Q2 is 3

Just cut the list of number into quarters

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5. Carlotta's Beauty Supply store sells two brands of bar soap. A 6 pack of Brand A costs

vekshin1

I think it would be be because you’re actually saving a little bit more amount of money you’re paying a dollar and would say two cent for each bar

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3 years ago

Tasha eats half her snack and gives the other half to two of her best friends to share equally. What portion of the whole snack

dybincka [34]

Answer:

tasha got 1/2 of it

one friend got 1/4 of it

the other friend got 1/4 of it

Step-by-step explanation:

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3 years ago

Read 2 more answers

Explain how to use 8×5=40 to find 8×6.

Zina [86]

Answer:

Well there are many different ways to find 8x5=40 to 8x6=__

You could add 8 to 40 and get 48.

or you could draw pictures to represent the 48.

8x6=48

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3 years ago

For sin2x+cosx=0, use a double-angle or half-angle formula to simplify the equation and then find all solutions of the equation

Archy [21]

Answer:

Step-by-step explanation:

Given is a trignometric equation in x, as

$sin2x+cosx=0$

TO make it in one trig ratio, we can replace sin2x as 2sinx cosx

WE get now

$2sinxcosx+cosx=0\\$

$cosx(2sinx+1)=0\\cosx=0, sinx =-0.5\\$

Principal solution is $x=\frac{\pi}{2} , \frac{-\pi}{6}$

x = ±π/2 + 2kπ, where k is any integer or

x=±pi/6 +k pi, where k is any integer.

General solution is

4 0

3 years ago

The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle

ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use w to represent the width, the length will be 6 more than 2 times w.

Hence, the length is $2w+6$ .

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

$A=w(2w+6)$

We can also substitute 40 in for A as it's given in the question.

$40 = w(2w+6)$

Distributing w by multiplying it by both terms in the parentheses, we get

$40 = 2w^2+6w$

We can make the equation simpler by dividing both sides by 2.

$20 = w^2+3w$

Subtracting both sides by 20 will make the left-hand side 0.

$0=w^2+3w-20$

Now that we have put this quadratic equation into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

$w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}$

$w= \frac{-3\pm\sqrt{9+80}}{2}$

$w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}$

Since the second solution results in a negative number, it cannot be the length of w.

$w=\frac{-3+\sqrt{89}}{2}\approx3.217$

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

$l=2(3.217)+6$

$l=12.434$

The length of this rectangle is 12.434 cm.

6 0

1 year ago