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melisa1 [442]
3 years ago
5

For the first four days of a five day vacation, the mean temperature was 80 degrees. What must the temperature be on the fifth d

ay in order for the mean temperature to be 82 degrees?
Mathematics
1 answer:
V125BC [204]3 years ago
6 0

Answer:

The 5th day must be 90

Step-by-step explanation:

The first 4 days averaged out to 80

You can find their total just by multiplying by 4. That won't tell you the exact values, but it will tell you their total when you add the 4 of them together.

80*4 = 320

Now you need to add another day into the mix. Call it x

320 + x

Now there are 5 days, not 4, and the new total is 82.

(320 + x) / 5 = 82          Multiply both sides by 5

5*(320 + x) / 5 = 82 *5

320 + x = 410                 Subtract 320

-320        -320

x = 90

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|4x + 4| = 15

First, let's get rid of the absolute value signs to get the first solution.

4x + 4 = 15

Subtract 4 from both sides

4x = 11

Divide each side by 4

x = 11/4 or 2.75

Now, let's get the solution by changing 15 to -15.

4x + 4 = -15

Subtract 4 from both sides

4x = -19

Divide both sides by 4

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The width of a rectangle is the length minus 2 units. The area of the rectangle is 15 units. What is the width, in units, of the
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Answer:

The answer to your question is width = 3

Step-by-step explanation:

Data

width = w = ?

length = l = ?

Area = 15 units

Process

1.- Write equations to help to solve this problem

   Area of a rectangle = width x length

                                    = w x l                         Equation l

   width = length - 2

         w = l - 2                                                  Equation ll

2.- Substitution

                            A = w x l

                          15 = (l - 2)(l)

3.- Expand

                          15 = l² - 2l

                           l² - 2l - 15 = 0

2.- Solve for l

-Find the prime factors of -15

                          15   3

                            5  5

                             1

     15 = 3 x 5

3.- Factor l² -2l - 15 = 0

                (l - 5)(l + 3) = 0

4.- Find the values of l

                 l₁ - 5 = 0            l₂ + 3 = 0

                 l₁ = 5                 l₂ = -3

The length if the rectangle = 5, it could not be -3, because there are no negative lengths.      

5.- Find w

                   w = l -2

                   w = 5 - 2            

                   w = 3 units

                           

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