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velikii [3]
3 years ago
11

Definition of Solid State of Matter

Chemistry
1 answer:
Oksanka [162]3 years ago
5 0
Solid state of matter
- the atoms are tightly packed in orderly form, they slightly vibrate but are stuck in a fixed position. Solids cannot be compressed and they maintain their shape
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Enter your answer in the provided box. an aqueous solution containing 10 g of an optically pure substance was diluted to 500 ml
sladkih [1.3K]

Answer:

[α] = -77.5° / \frac{\textup{dm-g}}{\textup{mL}}

Explanation:

Given;

Mass of optically pure substance in the solution = 10 g

Volume of water = 500 mL

Length of the polarimeter, l = 20 cm = 20 × 0.1 dm = 2 dm

measured rotation = - 3.10°

Now,

The specific rotation ( [α] ) is given as:

[α] = \frac{\alpha}{c\times l}

here,

α is the measured rotation = -3.10°

c is the concentration

or

c = \frac{\textup{Mass of optically pure substance in the solution}}{\textup{Volume of water}}

or

c =  \frac{10}{500}

or

c = 0.02 g/mL

on substituting the values, we get

[α] = \frac{-3.10^o}{0.02\times2}

or

[α] = -77.5° / \frac{\textup{dm-g}}{\textup{mL}}

7 0
4 years ago
What is 1.23 x 10^-3 in standard notation
Andrew [12]

Answer:

=0.00123

Explanation:

Look at the attachments below

Hope this helps (:

6 0
3 years ago
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What is a chemical bond?
hodyreva [135]
A chemical bond is <span> lasting attraction between atoms that enables the formation of </span>chemical <span>compounds. </span>
8 0
3 years ago
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A gas has a pressure of 450 mmHg at 100 degrees Celsius. What will its new pressure be when the temperature rises 200 degrees Ce
Ahat [919]

Answer:

P2 = 900 mmHg.

Explanation:

Given the following data;

Initial pressure = 450 mmHg

Initial temperature = 100°C

Final temperature = 200°C

To find the final pressure, we would use Gay Lussac's law;

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

\frac{P1}{T1} = \frac{P2}{T2}

Making P2 as the subject formula, we have;

P_{2}= \frac{P1}{T1} * T_{2}

P_{2}= \frac{450}{100} * 200

P_{2}= 4.5 * 200

Final pressure, P2 = 900 mmHg.

3 0
3 years ago
Most favourable conditions for electrovalency are
anygoal [31]

Answer:

I think

Explanation:

low charge of ions, large cation and small anion

7 0
4 years ago
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