Answer: Thus 293 moles of Oxygen gas can be stored in a standard gas cylinder at a temperature of 
and a pressure of 15200 kPa
Explanation:
According to ideal gas equation:
P = pressure of gas = 15200 kPa =150 atm (1kPa=0.0098atm)
V = Volume of gas = 47 L
n = number of moles = ?
R = gas constant =
T =temperature =
Thus 293 moles of Oxygen gas can be stored in a standard gas cylinder at a temperature of and a pressure of 15200 kPa
(1.1232 * 10⁵) (6.022 * 10¹⁷)
Now, multiply simple numbers together and exponentials, together:
= 1.1232 * 6.022 * 10⁵ * 10¹⁷
= 6.763 * 10²²
In short, Your Answer would be 6.763 * 10²²
Hope this helps!
Answer:
AYYYY I NEED POINST NOW NOW NO WNO WNOW
Explanation:
T = final temperature of the block
T₀ = initial temperature of the block = 23.4 °C
Q = energy lost from the wooden block = - 759 J
c = specific heat capacity of wood = 1.716 J/(g °C)
m = mass of the wooden block = 27.2 g
Heat lost from the block is given as
Q = m c (T - T₀)
inserting the values
- 759 = (27.2) (1.716) (T - 23.4)
T = 7.1 °C
Answer:
I hope that the answer helps. I did not round the final answer, maybe you want the answer in a specific decimal place!
Explanation:
