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3 years ago

Solid to liquid change melting

Chemistry

1 answer:

Maurinko [17]3 years ago

3 0

Answer:

The process of a solid becoming a liquid is called melting. (an older term that you may see sometimes is fusion). The opposite process, a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting point—is a characteristic of that substance.

Hope this helps, have a wonderful day/night, stay safe, happy holidays, and merry christmas!

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3 years ago

Read 2 more answers

The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins

saul85 [17]

The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^{n} = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
 $t_{1/2}$ - half-life
t - total time elapsed
n - a number of half-lives

So, we know:
t = 10 min
 $t_{1/2}$ = 2.5 min

We need:
n = ?
x = ?

We could first use the second equation to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{10 min}{2.5 min}$
⇒ $n=4$ 

Now we can use the first equation to calculate the remained fraction of the sample.
 $(1/2)^{n} = x$
⇒ $x=(1/2)^4$
⇒ $x= \frac{1}{16}$

3 0

3 years ago

How many grams of AlCl3 (Molar mass =133.5 g/mol) are needed to prepare 125 mL of a 0.150 M solution?

Gnesinka [82]

Answer:

2.50 g of AlCl3

Explanation:

Goodness, stoichiometry...

So, what we need to find first is the amount of grams of AlCl3. To do this we look at the formula of molarity.

M = mols/L of solvent

So we know two parts of this formula. We have the Molarity (0.150) and the mL (125).

Now, we can't forget that we must convert 125 mL into liters so we have 0.125 L ( I forgot and had to do the entire problem again...)

So if we do the backwards equation we get:

0.150 = x/0.125

If we do math (fun ikr) we get 18.75 mols of the solution.

Now, we have to plug this wonderful number into stoichiometry

0.01875 mols | 133.5 g

| 1 mol AgCl3

If you are unfamiliar with what I'm doing, I'm basically going to multiply 0.01875*133.5 then divide that whole thing by 1.

So, I got 2.503125 g AlCl3

If your teacher is a stickler for significant figures there are 3 sig figs for this problem so your final answer should be

2.50 g of AlCl3

Hope you have a great day and fun with chemistry!!!!

4 0

3 years ago

Solid to liquid change melting​

Solid to liquid change melting