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adelina 88 [10]
2 years ago
7

It takes 93.75 mL of a 0.200 M NaOH to neutralize 75.0 mL of an unknown

Chemistry
1 answer:
borishaifa [10]2 years ago
5 0

Answer:

the answer is the second option

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For the reaction2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)ΔH° is -125 kJ/mol and ΔS° is +253 J/K ∙ mol. This reaction is _
ivanzaharov [21]

Answer:

C. spontaneous at all temperatures

Explanation:

The spontaneity of  reaction is determined by the sign of the  gibbs free energy.

A negative sign denotes that the reaction is spontaneous, positive sign means the reaction is not spontaneous.

From the question;

ΔS° = +253 J/K

ΔH° = -125 kJ/mol

ΔG = ΔH°  - TΔS°

From the data given, the condition in which we can obtain a negative value of G, is at any value of T.

For any value of T, G would always be a negative value.

This means the correct option is option C.

3 0
3 years ago
Write 10,847,100 in Scientific Notation with 4 significant figures.
masha68 [24]

Answer:

The number 10,847,100 in Scientific Notation is 1.0847x10^{7}

Explanation:

Scientific notation is an easy form to write long numbers and it is commonly used in the scientific field. To write a long number in a shorter way it is necessary to 'move' the decimal point to the left the number of positions that are necessary until you get a unit. Then you write the number and multiplied it by 10 raised to the number of positions you moved the decimal point. In this case, it is necessary to move the decimal point 7 positions so, we multiply the number by 10 raised to 7.

5 0
3 years ago
Suppose a student made a different sodium hydroxide solution using 0.401g of solid sodium hydroxide and 200mL of water. The stud
telo118 [61]

Answer:

0.05 M

Explanation:

Mass of benzoic acid= 0.158g

Volume of benzoic acid= 100 mL

Volume of sodium hydroxide = 27.84mL

Molar mass of benzoic acid= 122g/mol

Number of moles of benzoic acid= 0.158g/122g/mol= 1.3 × 10^-3 moles

C= no of moles/volume

C= 1.3 × 10^-3 moles × 1000/100

C= 0.013M

So;

Volume of acid VA = 100mL

Concentration of acid CA= 0.013M

Volume of Base VB = 27.84mL

Concentration of Base CB= ???

Number of moles of acid NA =1

Number of moles of Base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CB= CAVANB/VBNA

CB= 0.013 × 100 × 1/27.84 × 1

CB= 0.05 M

4 0
3 years ago
In your own words can yall give me a example of air pollution/
raketka [301]
Sulfur dioxide is an example of air pollution.
It is the main component of acid rain. It is released into the air as a result of the burning of fossil fuels.

3 0
3 years ago
Read 2 more answers
ASAP WHAT ARE THE ANSWERS FOR 3,4,5,6
storchak [24]
3 should be B hop this helps
3 0
3 years ago
Read 2 more answers
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