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valentinak56 [21]
3 years ago
7

What is the name of the shape graphed by the function r= 3+ 3 cos theta?

Mathematics
2 answers:
34kurt3 years ago
8 0

Answer: Cardioid

Step-by-step explanation:

disa [49]3 years ago
6 0

Answer:

cardioid

Step-by-step explanation:

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Solve by substitution <br> X^2= 2y + 10<br> 3x-y = 9
Viefleur [7K]

Answer:

x=-4\\ x=-2\\ y=-21\\ y=-15

Step-by-step explanation:

x^{2} =2y+10

y=-9+3x

x^{2} =2(-9+3x)+10

x^{2} =-18+6x+10

x^{2} =6x-8

x^{2} -6x+8

x=-4, -2

y=-9+3(-4)

y=-9-12

y=-21

y=-9+3(-2)

y=-9-6

y=-15

8 0
4 years ago
Read 2 more answers
The table shows the decay rate for a certain radioactive material over time. In this context, what does the y-intercept represen
djyliett [7]

Answer:

At 0 hours, there are 100 grams of the substance remaining.

Step-by-step explanation:

4 0
2 years ago
Is 1/3 and 2/6 equivalent
Helga [31]
Yes because 2/6 divided in half is 1/3
8 0
3 years ago
Read 2 more answers
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
A line that includes the point (0, 9) has a slope of 9. What is its equation in slope-intercept
Rufina [12.5K]
Slope intercept: y = mx + b
Y = 9x + b, plug in point
9 = 9(0) + b, b = 9
Solution: y = 9x + 9
7 0
3 years ago
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