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3 years ago

Algebra 2B U2 L6 Function Operations practice 8-10

Mathematics

1 answer:

Bess [88]3 years ago

6 0

Answer:

1) f(g(0)) = 0

2) g(f(2)) = 2

3) g(g(0)) = 8

Step-by-step explanation:

Here, the given functions are:

g(x) = 3 x +2 and f(x)= (x-2)/3

1. Now, f(g(x)) = f(3x+2)

Also, f(3x+2) = (3x+2 -2) /3 = x

So, f(g(x)) = x

⇒ f(g(0)) = 0

2. g(f(x)) = g((x-2)/3) = 3((x-2)/3) +2

or, g(f(x)) = x

⇒ g(f(2)) = 3((2)-2/3) +2 = 2

or, g(f(2)) = 2

3. g(g(0)= g( 3 (0) +2) = g(2)

Now, g(2) = 3(2) + 2 = 6 + 2 = 8

or, g(g(0)) = 8

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