Answer:
Step-by-step explanation:
The negative of a negative is the opposite positive number. When you subtract a positive integer from a negative integer, the difference is always negative. When you subtract two negative integers and the first integer is smaller than the second integer , the difference is negative.
(16x^1/6y^-2)^3/2 / (x^-1/6y^6)^3/2
=(4^2)^3/2 (x^1/6)^3/2 (y^-2)^3/2 / (x^-1/6)^3/2(y^6)^3/2
= 4^3 x^1/4 y^-3 / x^-1/4 y ^9
= 64 x^(1/4 +1/4) y^(-3-9)
= 64 x^1/2 y^-12
= 64 x^1/2 / y^12
answer is D.64 x^1/2 / y^12
Answer:
x = 3(6 + y)/2
Step-by-step explanation:
Solving for x
Add 3y to both sides.
2x = 18 + 3y
Divide both sides by 2.
x = 18 + 3y/2
Factor out the common term 3.
x = 3(6 + y)/2