There are 8 airplanes...maybe...check me on a calculator....
Answer:
a). true
b). true
Step-by-step explanation:
a).
Given : If a = 5, then ac = 5c
Let c be any constant.
a = 5 (given)
Therefore, ac = 5c
Here a is given a constant value (5), also let assume c to be a constant. So when we multiply each term we will get a constant value of 5c. The ratio does not change.
Hence proved.
b).
Given : If ac = 5c, then a = 5
Let c be any constant
It is given, a = 5
Therefore, ac = 5c
Here the product of two terms is given as 5c, where c is assume to be a constant. Then as a product rule, the value of a will be 5. The ratio will not change.
Hence proved.
Answer is 127.15
to google the formula of volume of sphere
We are given with the radical expression
√(27 x⁴ / 75 y²)
we can simplify this by dealing with the fraction first
√(27 x⁴ / 75 y²) = √( 9 x⁴ / 25 y²)
Then, take the square root of the coefficients and the variables
= 3x² / 5y<span />
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
