Hello,
f(x) has as inverse f^(-1)(x) 
and (fof^(-1))(x)=(f^(-1)of)(x)= x (the neutral function)
so h(f(x))=x
        
                    
             
        
        
        
Answer:
20 units^2
Step-by-step explanation:
5 x 4
20
 
        
                    
             
        
        
        
The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:

Differentiate the function with respect to t

Set to 0

So, we have:

Collect like terms


Solve for t


Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
 
        
             
        
        
        
The parallel lines have the same slope.
The slope-intercept form: y = mx + b
m - a slope.
We have 6x + y = 4     |subtract 6x from both sides
y = -6x + 4 → m = -6.
The slope-point form:

We have m = -6 and (-2, 3).
Substitute:

<h3>Answer: 6x + y = -9.</h3>
 
        
             
        
        
        
Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c 
x^2 - 2x - 13
a = 1     b = -2    c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74 
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74