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Triss [41]
3 years ago
15

. How many minutes is it from 23:35 today to 01:15 tomorrow?

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

A (100)

Step-by-step explanation:

If 2 hours pass starting at 23:35 today, then tomorrow the time will be 1:35. The difference between 1:35 and 1:15 is 20 (minutes) Because there are 120 minutes in 2 hours (60 minutes per hour), This means we do 120 minutes minus 20 minutes. This gives us an answer is A, 100 :)

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How many solutions does this equation have? <br><br><br> 7a+5(a+3) = 8a+4(a+2)
nikitadnepr [17]

Answer:

There is no solution

Step-by-step explanation:

4 0
3 years ago
Please help me ASAP!Please this is due soon and i don't have all day.
Helga [31]

<u><em>Answer:</em></u>

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

<u><em>Explanation:</em></u>

<u>The formula to calculate the percent change in mass is given as:</u>

PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100

<u>1- Section 1:</u>

Old mass = 7.83 g and New mass = 8.268 g

PercentChange = \frac{8.268-7.83}{7.83}*100 =5.59%

<u>2- Section 2:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.4}*100 =-2.16%

<u>3- Section 3:</u>

Old mass = 7.3 g and New mass = 6.51 g

PercentChange = \frac{6.51-7.3}{7.3}*100 =-10.82%

<u>4- Section 4:</u>

Old mass = 7.49 g and New mass = 7.0 g

PercentChange = \frac{7.0-7.49}{7.49}*100 =-6.54%

<u>5- Section 5:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.7.4}*100 =-2.16%

<u>6- Section 6:</u>

Old mass = 7.89 g and New mass = 8.51 g

PercentChange = \frac{8.51-7.89}{7.89}*100 =7.86%

Hope this helps :)

6 0
3 years ago
Can I have help please on 1-5
BigorU [14]

Answer:

1-5=4 DUHHHHHHHHH

Step-by-step explanation:

5 0
3 years ago
A quality engineer measured 75 bolts. The length (in mm) and the number of flaws on each of 75 bolts is recorded.
andre [41]

Answer:

i)

Variables: length of bolt, number of flaws of bolt

ii)

Length of bolt: Quantitative continuous

number of flaws of bolt: Quantitative discrete

iii)

Observational unit: Bolts

iv)

sample size=75

Step-by-step explanation:

i)

The variables in the conducted study are "length of bolt" and "number of flaws on each bolt" because quality engineer is interested in evaluating the length of bolt and the number of flaws each bolt is having. Thus, the length and number of flaws for each bolt varies and we can say that "length of bolt" and "number of flaws on each bolt" are two variables in the conducted study.

ii)

The length of bolt can be presented numerically and further that the length of a bolt is measurable and thus, the length of bolt is a quantitative continuous variable.

The number of flaws of each bolt can be presented numerically and further that the number of flaws of each bolt can be counted and thus, the number of flaws of each bolt is a quantitative discrete variable.

iii)

The conducted study indicates that observational units are "bolts" because for each bolt its length and flaws are determined.

iv)

The sample size is 75 because a quality engineer selected 75 bolts and then measured its length and flaws.

6 0
4 years ago
Which is the graph of f (x) = 3 (two-thirds) Superscript x?
Contact [7]

Shown below

<h2>Explanation:</h2>

The function is as follows:

f(x)=3(\frac{2}{3})^x

This is an exponential decay because 2/3. So, let's find some important points:

y-intercept:

This occurs when x=0, so:

f(x)=3(\frac{2}{3})^x \\ \\ f(x)=3(\frac{2}{3})^0 \\ \\ f(x)=3(1) \\ \\ f(x)=3 \\ \\ \\ So, \ point \ (0,3) \ is \ solution \ to \ the \ graph \ of \ the \ function

Find another point:

For \ x=1 \\ \\ f(x)=3(\frac{2}{3})^1 \\ \\ f(x)=2 \\ \\ \\ So, \ point \ (1,2) \ is \ also \ a \ solution

Finally, the exponential function passes through these two points as indicated below.

<h2>Learn more:</h2>

Exponential functions: brainly.com/question/1854704

#LearnWithBrainly

7 0
4 years ago
Read 2 more answers
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