An ellipse has a vertex at (14, –1). The focus of the ellipse nearest that vertex is located at (8, –1). If the center of the el
lipse is located at (–1, –1), what is the equation of the directrix on that side of the ellipse?
x =
x =
2 answers:
Refer to the diagram shown below.
The right vertex is at (14, -1), and the center is at (-1, -1).
Therefore the semi-major axis is
a = 14 - (-1) = 15
The right focus is at (8, -1).
Therefore
c = 8 - (-1) = 9.
The distance of the directrix from the center is
d = c²/a = 9²/15 = 81/15 = 27/5.
Therefore the equation for the left directrix is
x = -1 - 27/5 = -32/5
Answer: x = -27/5
The right vertex is at (14, -1), and the center is at (-1, -1).
Therefore the semi-major axis is
a = 14 - (-1) = 15
The right focus is at (8, -1).
Therefore
c = 8 - (-1) = 9.
The distance of the directrix from the center is
d = c²/a = 9²/15 = 81/15 = 27/5.
Therefore the equation for the left directrix is
x = -1 - 27/5 = -32/5
Answer: x = -27/5
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Answer:
Step-by-step explanation:
The given expression is
First, we need to factor each denominator
So, the least common factor (LCF) is , because they are the factors that repeats.
Now, we diviide the LCF by each denominator, to then multiply it by each numerator.
Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.
Therefore, the expression is equivalent to