Answer:
its answer J,F,M,A,M,J,J
Step-by-step explanation:
<h3>its a name of months next 5 words is A,S,O,N,and D</h3>
Answer:
x=-5.5
Step-by-step explanation:
-3(x+4)=(-x-1)
1. Distribute
-3x+(-12)=-x-1
2. Simplify
-3x-12=-x-1
-2x-12=-1
-2x=11
x=-11/2
x=-5.5
Answer:
Step-by-step explanation:
Given a function
, we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "
" to another "
".
The rate of change of
between
and
can be calculated as follows:

For:

Let's find
and
, where:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

So:

And for:

Let's find
and
, where:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

So:

<em>Translation:</em>
Dada una función
, llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "
" a otro "
".
La tasa de variación de
entre
y
, puede ser calculada de la siguiente forma:

Para:

Encontremos
y
, donde:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

Entonces:

Y para:

Encontremos
y
, donde:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

Entonces:

Answer:
C. Mrs. Alvarez's scores were less spread out than Mr. Crawford's scores.
Step-by-step explanation:
Mean Absolute Deviation is one of the Statistical measures which we can you to determine the variation that exist amongst a given set of data
Mean Absolute Deviation can be defined as how far or the distance between one set of data to another set of data.
The smaller the Mean Standard Deviation, the lower the degree of variation in the set of data. The data is less spread out
The larger the Mean Standard Deviation, the higher the degree of variation in the set of data. The data is Largely spread out
We are told in the question that:
Mrs. Alvarez's scores had a lower mean absolute deviation than Mr. Crawford's scores. Our conclusion would be that Mrs. Alvarez's scores were less spread out than Mr. Crawford's scores.
Option 2 is correct.