the father divide a number of his cows to his thee sons Mongo,masuu and muzo a half of it was given to Mongo and 3/4 of the rema
ining to musuu while muzo get the remaining which were 25cows.find cows were distributed
1 answer:
Answer: Original number of cow = 200
Mongo receive = 100 cow
Masuu receive = 75 cow
Muzo receive = 25 cow
Explanation:
Let x be the original number of cow:
And x = 100%
Mongo = x/2 = 100%/2 = 50%
Thus, mongo receive 50% of the cow and the other 50% are divide to masuu and muzo.
50% = 3/4 + 1/4
Where 3/4 was given to masuu and 1/4 was given muzo.
But muzo receive 25 cow as a remaining thus, 1/4 = 25
If 1/4 = 25 then 3/4 = 75
Therefore, 50% = (75 + 25)cow
50% = 100 cow
But Mongo receive half of the original cows. Which mean he receive 100 cows.
Original number of cow = 100 + 75 + 25 = 200 cows
You might be interested in
Second side= x
First side = 2x
Third side = x+5
x+2x+x+5=49
4x=44
x=11
1st side= 22
2nd side = 11
3rd side = 16
1.25 kg is the original weight
1.1kg= 88% of the original weight
(100-12)
Answer:
gwrbcu7gbw57r t23bwuevy 23uwbev 3u b
Step-by-step explanation:
Box 1: 6 Box 2: 16 Box 3: 20 Box 4: 24