Given:
The expression is
![\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%20%5C_%5C_%7D%3D)
To find:
The simplified form of the expression.
Solution:
We have,
![\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%20%5C_%5C_%7D%3D)
The expression
can be written as
![\sqrt[3]{48}=\sqrt[3]{8\cdot 6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%206%7D)
![[\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5B3%5D%7Bab%7D%3D%5Csqrt%5B3%5D%7Ba%7D%5Csqrt%5B3%5D%7Bb%7D%5D)
![\sqrt[3]{48}=2\cdot \sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D2%5Ccdot%20%5Csqrt%5B3%5D%7B6%7D)
![\sqrt[3]{48}=2\sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D2%5Csqrt%5B3%5D%7B6%7D)
Therefore,
.
Answer:
The center of the circle is

Step-by-step explanation:
Let the equation of the circle be
, where (-a,-b) is the center of this circle.
The points lying the circle must satisfy the equation of this circle.
A(0,0)
We substitute this point to get;


B(-3,0)



But c=0


C(1,2)



Put the value of 'a' and 'c' to find 'b'




b=-2
Hence the center of the circle is

9514 1404 393
Answer:
A: (3x +4)
B: (4x +5y) × (4x -5y)
Step-by-step explanation:
<u>Part A</u>:
Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.
9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²
The side of the square is 3x+4.
__
<u>Part B</u>:
The difference of squares is factored like this:
a²-b² = (a +b)(a -b)
The given area expression is the difference of squares with ...
a = 4x, b = 5y
so, the factorization is ...
16x² -25y² = (4x +5y)(4x -5y)
The dimensions of the rectangle are (4x+5y) by (4x-5y).
EDIT: Picture
33) When adding matrices, just add the numbers that are in the same spot. In this problem we are given A and C, and we are asked to find B if A + B = C
So B = C - A
![\left[\begin{array}{ccc}2&-1&-3\\1&4&-2\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%26-3%5C%5C1%264%26-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
-
![\left[\begin{array}{ccc}4&9&-2\\-3&5&7\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%269%26-2%5C%5C-3%265%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
=
![\left[\begin{array}{ccc}-2&-10&-1\\4&-1&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-10%26-1%5C%5C4%26-1%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
34) When multiplying matrices, the number of columns in the first matrix needs to be the same as the number of rows in the second matrix. Then the outcome will have the same number of rows as the first matrix and same number of columns as the second matrix. In this case, the result will be a 2x2.