All categories

2 years ago

Which of the following equations have no solutions?

Mathematics

2 answers:

Ksju [112]2 years ago

7 0

Answer:

Step-by-step explanation:

-4x-5=-4x-4

+4x +4x

4x cancels out and goes away so there is no solution

ElenaW [278]2 years ago

7 0

The answer is C hope this helps :)

You might be interested in

Kaylee and her mom went to the craft store to buy supplies to make a costume for kaylee school play. They needed 3 1/2yards of g

serious [3.7K]

$12 1/2 hope this helps

3 0

3 years ago

How is 16/7 simplified???????

zloy xaker [14]

You can write as 2 2/7

3 0

3 years ago

Which shows another way to write 64?

Taya2010 [7]

None of those show another way to 64

6*6*6*6=1296

4*4*4*4*4*4=4096

6+6+6+6=24

6*4=24

Another way to show 64 is 8*8 or 4^3

4 0

3 years ago

Someone plz help me :(

8090 [49]

Answer:

A, 360 minutes= 6 hours.

<em>I hope this helped at all.</em>

4 0

2 years ago

Read 2 more answers

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0

3 years ago