If we have a square with an area of 75 square meters, what would the side length be?
2 answers:
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Answer:
42.64°
Step-by-step explanation:
Note: A rhombus has all its sides equal, its opposite angle are equal, its has bigger and smaller diagonal, diagonal bisect the angles and diagonal bisect each other.
From the diagram attached,
sinθ = opposite/adjacent
sinθ = 4/11
θ = sin⁻¹(4/11)
θ = 21.32
Therefore, from the diagram,
The smaller angle of the rhombus = 2θ
The smaller angle of the rhombus = (2×21.32)
The smaller angle of the rhombus = 42.64°
Answer:
l=0.1401P\\
w =0.2801P
where P = perimeter
Step-by-step explanation:
Given that a window is in the form of a rectangle surmounted by a semicircle.
Perimeter of window =2l+\pid/2+w
Or
To allow maximum light we must have maximum area
Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle
Hence we get maximum area when i derivative is 0
i.e.
Dimensions can be