The slope f'(x) = [f(4) - f(2)]/(4-2)≥3,
so [f(4) - 13]/2 ≥3
f(4) -13 ≥ 6
f(4)≥19, so it can be as small as 19.
Answer:
It's the second answer down : Angle B, A and C
Step-by-step explanation:
Answer:
Substitute, <em><u>y = -3</u></em> and <em><u>x = k</u></em> on the equation.
=> k - 2×(-3) = -2
=> k = -2 + (-6)
=> k = - 8
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<h2>HOPE U UNDERSTOOD</h2><h3>MARK AS BRAINLIEST ONE</h3>
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Answer with Step-by-step explanation:
We are given that

We have to explain that why the function is discontinuous at x=2
We know that if function is continuous at x=a then LHL=RHL=f(a).

LHL=Left hand limit when x <2
Substitute x=2-h
where h is small positive value >0


Right hand limit =RHL when x> 2
Substitute
x=2+h


LHL=RHL=
f(2)=1

Hence, function is discontinuous at x=2
Answer:
IT WOULD BE 2.5 IN decimal form or it would be 5/2 and it is equivalent to 2 and 1/2
Step-by-step explanation: