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4 years ago

14

A delivery truck travels 21 blocks north, 12 blocks east and 26 blocks south. what is its final displacement from the origin? as

sume the blocks are equal length.

1 answer:

irakobra [83]4 years ago

4 0

The displacement is 13 blocks since its last position is 5 blocks south and separated 12 blocks east. We got 13 blocks by using triple phytagoras.

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. there are multiple sockets that can be interchanged easily to accommodate many different size nuts and bolts

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4 years ago

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Cubic functions usually look like an S

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3 years ago

Find the slope of the line that passes through the points (1,-4) and (3,-1).

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3 years ago

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

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3 years ago

(4x^4 - 14x^3 + 11) - (-14x^6 - 9x^5 - 12x^2) <br><br> Please simplify

yulyashka [42]

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3 years ago