Answer & step-by-step explanation:
Stationary points are the points where the first derivative is equal to zero.
Let's calculate it using the power rule (exponent comes forward, decrease exponent by 1) and the fact that the derivative is a linear operation (that is
)
The first derivative is then

Note that the last passage is not strictly needed, but it's really helpful to find stationary points, when in this next passage we set it equal to zero. Alternatively, you can use the quadratic formula if you can pull the factors out of your head right away.

These two point could be maxima, minima, or inflection points. To check them you can either see how the sign of the first derivative goes, or check the sign of the second derivative, as you're required.
The rules states that if the second derivative evaluated in that point is negative we have a maximum, if it's positive we have a minimum, and if we have a zero we keep derivating until we get a non-zero value.
In our case, the second derivative we get by calculating the derivative again and we get
. Evaluating it at both points we get

so -2 is a maximum and 3 is a minimum.
Answer:i have same question
Step-by-step explanation:
Answer:
do the calculation below
Step-by-step explanation:
(4/52 ) *(3/51)
leave a comment if you need more help
Step-by-step explanation:
In set a, every element in the domain has only 1 image in the range. This is called a one-to-one correspondence.
However in set b, there is a many-to-one correspondence as more than 1 element in the domain has the same image.
Answer:
Option C. 
Step-by-step explanation:
we know that
The equation of the parent function f(x) (red graph) is

This is a vertical parabola open upward
The vertex is the point (0,0) (the origin)
The function g(x) (blue graph) is a vertical parabola open upward
The vertex is the point (-5,0)
The transformation of f(x) to g(x) has the following rule
f(x) -----> g(x)
(0,0) ----> (-5,0)
(x,y) ----> (x-5,y)
That means----> The transformation is a translation of 5 units at left
therefore
The equation of g(x) is
