Split up the interval [0, 3] into 3 equally spaced subintervals of length 
. So we have the partition
[0, 1] U [1, 2] U [2, 3]
The left endpoint of the 
-th subinterval is
where 
.
Then the area is given by the definite integral and approximated by the left-hand Riemann sum
M=4
first we take the 4.5 to the other side and we also take the 12 to other side so we get
1.5m=6
we divided each side we get m=4
T could be located at 15 because 5 plus 15 equals 20
k = 18
the common difference d of an arithmetic sequence is
d = a₂ - a₁ = a₃ - a₂ = ....
a₂ - a₁ = 2k - 1 - k - 9 = k - 10 and
a₃ - a₂ = 2k + 7 - (2k - 1) = 2k + 7 - 2k + 1 = 8, hence
k - 10 = 8 ⇒ k = 8 + 10 = 18
the 3 consecutive terms are
27, 35, 43
