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2 years ago

What two numbers have a product of -15 and a sum of -2

Mathematics

1 answer:

Strike441 [17]2 years ago

4 0

Answer:

5 and -3

Step-by-step explanation:

5 x (-3) = -15

5 + (-3) = -2

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Order the numbers from least to greatest. List the numbers as your final answer. 4, 7, -2, 25, 49, 63, 13, -22, 19, -13, 4/4, 34

sp2606 [1]

-22 , -13, -3, -2 , 4/4, 4, 7, 13, 19, 25, 34, 49, 63

4 0

3 years ago

Read 2 more answers

If f(x) = x and g(x) = 2x + 7, what is<br>f[90X)] when g(x) = 11?

kumpel [21]

$\bf \begin{cases} f(x) = x\\ g(x) = 2x+7 \end{cases}~\hspace{7em}g(x)=11\implies \stackrel{g(x)}{11}=2x+7 \\\\\\ 4=2x\implies \cfrac{4}{2}=x\implies \implies \boxed{2=x} \\\\[-0.35em] ~\dotfill\\\\ f[90x]\implies f\left[90\left( \boxed{2} \right)\right]\implies f(180)=\stackrel{x}{180}$

8 0

3 years ago

Slope = 4/3, (-2, 11)

Lady_Fox [76]

Answer:

y = $\frac{4}{3}$ x + $\frac{41}{3}$

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

here m = $\frac{4}{3}$ , hence

y = $\frac{4}{3}$ x + c ← is the partial equation

to find c substitute (- 2, 11) into the partial equation

11 = - $\frac{8}{3}$ + c ⇒ c = $\frac{41}{3}$

y = $\frac{4}{3}$ x + $\frac{41}{3}$ ← equation of line

7 0

3 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

2 years ago

Johnny left home and drove west 6 miles to Bakersville for flowers. Then he drove 8 miles north to his girlfriend's house. How f

QveST [7]

So use pythagorean theorem to find the straight distance between hhouses

legs are 6 and 8

a^2+b^2=c^2
6^2+8^2=c^2
36+64=c^2
100=c^2
squrer root both sides
10=c

the distance=10 miles

6 0

3 years ago

What two numbers have a product of -15 and a sum of -2​

What two numbers have a product of -15 and a sum of -2