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2 years ago

Explain why 3x – y is the same as -y + 3.1.

Mathematics

1 answer:

asambeis [7]2 years ago

3 0

Answer:

The commutative property

Step-by-step explanation:

The commutative property of addition states that a+b=b+a ( i.e you can move things around without changing the sum)

example:

3x-y=3x+(-y)=(-y)+3=-y+3x

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HELP PLEASE and show work

larisa86 [58]

Answer:

$\boxed{\stackrel{\Large\frown}{PQS}\:= 222°}$

Explanation:

Since $\overline{PR}$ is a diameter, arc $\stackrel{\Large\frown}{PQR}\:= 180°.$

Given that $\angle{SUR} = 42°$ is a subtended central angle by two diameters,

$\stackrel{\large\frown}{RS} \:= 42°$ .

Using the rule of arcs, $\stackrel{\Large\frown}{PQR} + \stackrel{\large\frown}{RS} \: = \: \stackrel{\Large\frown}{PQS}$ →

$180° + \: 42° = \: \stackrel{\Large\frown}{PQS}$

$222° = \: \stackrel{\Large\frown}{PQS}$

$\stackrel{\Large\frown}{PQS} \: = \: 222°$

3 0

2 years ago

Which equation is the inverse of y = 16x2 + 1?

Llana [10]

Answer:

$y=\frac{\sqrt{x-1} }{4}$

Step-by-step explanation:

The given equation is

$y=16x^2+1$

For this function to have an inverse, we must restrict the domain, say $x\ge0$

We interchange x and y to get,

$x=16y^2+1$

We now make y the subject to get;

$x-1=16y^2$

We divide through by 16 to get;

$\frac{x-1}{16}=y^2$

We now take the square root of both sides to get;

$\pm \sqrt{\frac{x-1}{16}}=y$

$y=\pm \frac{\sqrt{x-1} }{4}$

Since $x\ge 0$ , the inverse function is

$y=\frac{\sqrt{x-1} }{4}$

6 0

3 years ago

Is 2/8 equivalent to 3/12 Btw i suck at math HELP MEE

Scilla [17]

Answer:

yes

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Harman [31]

Answer: an improper fraction

Step-by-step explanation: An improper fraction is a fraction that is larger than 1 7/3 is larger than one because 7, the numerator is larger than the denominator so 7/3 is an improper fraction

3 0

1 year ago

Choose the inverse of y = x2 - 10x.

PilotLPTM [1.2K]

=Y2-10Y

We move all terms to the left:

-(Y2-10Y)=0

We add all the numbers together, and all the variables

-(+Y^2-10Y)=0

We get rid of parentheses

-Y^2+10Y=0

We add all the numbers together, and all the variables

-1Y^2+10Y=0

a = -1; b = 10; c = 0;

Δ = b2-4ac

Δ = 102-4·(-1)·0

Δ = 100

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

Y1=−b−Δ√2aY2=−b+Δ√2a

Δ‾‾√=100‾‾‾‾√=10

Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10

Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0

3 0

2 years ago