Answer:
3) 1 5/6 mi
4) a. 4 cm, 6 ft
b. 6.4 cm, 9.6 ft
c. same as part a
Step-by-step explanation:
3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...
4×1/3 + 4×1/8 = 4/3 + 4/8
= 1 1/3 + 1/2 = 1 2/6 + 3/6
= 1 5/6 . . . . . miles
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4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.
a. 8 cm = 4 cm + x
8 cm - 4 cm = x = 4 cm
The distance in the room is ...
(4 cm)×(1.5 ft/cm) = 6 ft
b. 10.3 cm = 3.9 cm + y
10.3 cm - 3.9 cm = y = 6.4 cm
The distance in the room is ...
(6.4 cm)×(1.5 ft/cm) = 9.6 ft
c. The answer to part b was obtained in the same way as the answer to part a. The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.
Step-by-step explanation:
2πrh+2πr²=surface area
2π(3)(6)+2π(3²)
36π+18π
54π
We have
SinC/ c = Sin A / a
Sin 71/ 26 = Sin A / 27
Sin A = 27 Sin 71 / 26 = about .982
So°
Sin-1(.982) = A = 79. 08°
Then angle B = 180 - 71 - 79.08 = 29.92°
And b is given by
b/sin29.92 = 26/sin 71
b = 26sin29.92/sin71 = about 13.72
But A could also be an obtuse angle = 180 - 79.08 = 100.92°
So we have
B = 180 - 71 - 100.92 = 8.08°
And we have
b / sin 8.08 = 26/sin71
b = 26sin8.08/sin 71 = 3.865
Complete question :
Chris has 7/8 yards of purple ribbon and 1 1/6 yards of green ribbon. Chris has a total of 3 2/3 yards of ribbon. How many yards of Chris's ribbon are neither purple nor green.
Answer:
1.625 yards
Step-by-step explanation:
Purple ribbon = 7/8 yards
Green ribbon = 1 1/6 yards = 7/6 yards
Total ribbon = 3 2/3 yards = 11/3 yards
Ribbon that is neither purple nor green :
Total ribbon - (green + purple ribbon)
7/8 - (7/6 + 7/8)
11/3 - (28 + 21) / 24
11/3 - 49/24
= 1.625 yards
