Answer:
I believe it's D.
Lmk if I was right, cause I'm 98% sure on this
The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
Answer:
Total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200
Step-by-step explanation:
We have given number of students = 10
These 10 students are assigned to four dorm rooms a single, a double, a triple and a quad
So number of ways to assigned single student 
Now left student = 10 -1 = 9
So number of ways to assigned double student 
Now left student = 9-2 = 7
So number of ways to assigned triple student
=70
Now left student = 7 - 3 = 4
So number of ways to assigned quad student 
So total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200
Answer:
the answer is 9 mark me brainlest
Step-by-step explanation:
A P E X
Answer:
3 peanut cookies
Step-by-step explanation:
Given that :
Plate 1:
Number of chocolate chip = 4
Number of peanut butter cookies = 1
Probability of drawing chocolate chip cookies from plate 1 :
Probability =( number of required outcome / Total possible outcomes)
P(chocolate chip) = 4 / 5
Plate 2:
Number of chocolate chip = 2
Number of peanut butter cookies = p
P(chocolate chip) = 2 / (2 + p)
Probability of drawing chocolate chip from plate 1 and then plate 2 = 8/ 25
(4/5) * 2/(2+p) = 8/ 25
8 / (10 + 5p) = 8/ 25
8(10 + 5p) = 8 * 25
80 + 40p = 200
40p = 200 - 80
40p = 120
p = 3